Business
Jobs
  • About Us
  • Solutions
    • Job Postings
      Post your job and receive qualified candidates in 48h.
    • Candidate Assessments
      500+ technical and psychological tests, plus anti-fraud.
    • Headhunting
      Tailor-made executive search from start to finish.
    • Payroll + EOR
      Payroll dispersal and EOR across 15+ LATAM countries.
  • Pricing
  • Jobs

0

207
Views
Cómo agregar un elemento a un div con className que tiene un elemento secundario con idName

MI html tiene varios divs que comparten el mismo nombre de clase y tienen elementos de entrada con identificadores únicos, quiero agregar un lapso debajo de todas estas entradas con JavaScript sin editar el html.

esta es la parte de html

 <form name="form" onsubmit="return validate();" method="get"> <div class="form-group"> <label for="pass">Password</label> <input type="password" class="form-control" name="pass" id="pass"> </div> <div class="form-group"> <label for="pass2">Re-Type Password</label> <input type="password" class="form-control" name="pass2" id="pass2"> </div> . . . </form>

este es mi JS para crear y agregar el lapso

 const errorMessage = document.createElement('span'); errorMessage.textContent = "invalid input"; document.querySelector('.form-group').appendChild(errorMessage);

Pero esto solo crea un lapso en el primer div

about 4 years ago · Juan Pablo Isaza
3 answers
Answer question

0

debe obtener todos los elementos que tienen un grupo de formularios de clase con querySelectorAll

 const arrayElement = document.querySelectorAll('.form-group'); for(let i = 0; i < arrayElement.length; i++) { const errorMessage = document.createElement('span'); errorMessage.textContent = "invalid input"; arrayElement[i].appendChild(errorMessage); }

más: https://jsfiddle.net/7znf685q/2/

about 4 years ago · Juan Pablo Isaza Report

0

Use querySelectorAll() e itere.

 querySelectorAll(".form-group").forEach(form => { const errorMessage = document.createElement('span'); errorMessage.textContent = "invalid input"; form.appendChild(errorMessage); });
about 4 years ago · Juan Pablo Isaza Report

0

querySelector solo obtiene la primera instancia. Debe usar querySelectorAll. Luego pon todo dentro de un bucle.

 let group = document.querySelectorAll('.form-group') for (let i = 0; i < group.length; i++) { const errorMessage = document.createElement('span'); errorMessage.textContent = "invalid input"; group[i].appendChild(errorMessage); }
 <form name="form" onsubmit="return validate()" method="get"> <div class="form-group"> <label for="pass">Password</label> <input type="password" class="form-control" name="pass" id="pass"> </div> <div class="form-group"> <label for="pass2">Re-Type Password</label> <input type="password" class="form-control" name="pass2" id="pass2"> </div> </form>

about 4 years ago · Juan Pablo Isaza Report
Answer question
Find remote jobs

Discover the new way to find a job!

Top jobs
Top job categories
Business
Post vacancy Pricing Sales
Legal
Terms and conditions Privacy policy
© 2026 PeakU Inc. All Rights Reserved.
Andres GPT
Show me some job opportunities
There's an error!