Business
Jobs
  • About Us
  • Solutions
    • Job Postings
      Post your job and receive qualified candidates in 48h.
    • Candidate Assessments
      500+ technical and psychological tests, plus anti-fraud.
    • Headhunting
      Tailor-made executive search from start to finish.
    • Payroll + EOR
      Payroll dispersal and EOR across 15+ LATAM countries.
  • Pricing
  • Jobs

0

88
Views
page doesn't display anything

so I wrote a script to display 5 random arrays, but the page doesn't display anything.
here's the code:

<html>
  <head>
    <script>
      function start(){
        var arr(5),result;
        result=document.getElementById("arraying");
        result="<p>";
        for(var i=0; i<5;i++){
          arr[i]=Math.floor(Math.random()*10);
          result+="arr["+i+"]= "+arr[i]+"</p><p>";
        }
        result+="</p>";
      }
      window.addEventListener("load",start,false);
    </script>
  </head>
  <body>
    <div id="arraying"></div>
  </body>  
</html>

I tried removing result=document.getElementById and write document.getElementById.innerHTML=result in the end of the function but didn't work. what's the error?

about 4 years ago · Juan Pablo Isaza
2 answers
Answer question

0

You cannot use the same variable for different purposes at the same time. First you assign a DOM element to result, and immediately on the next line you overwrite result with a string.

Build a string htmlStr inside your loop, and when that is done, assign this string to result.innerHTML property:

function start() {
  let arr = [],
    result, htmlStr = '';
  result = document.getElementById("arraying");
  htmlStr += "<p>";
  for (let i = 0; i < 5; i++) {
    arr[i] = Math.floor(Math.random() * 10);
    htmlStr += "arr[" + i + "]= " + arr[i] + "</p><p>";
  }
  htmlStr += "</p>";
  result.innerHTML = htmlStr;
}
window.addEventListener("load", start, false);
<div id="arraying"></div>

about 4 years ago · Juan Pablo Isaza Report

0

Looking at the code you seem to be missing some basic javascript concepts.

array size

This is probably your main issue:

var arr(5)

This does not make sense in javascript. Array length does not need to be predefined since all arrays are of dynamic length. Simply define an array like this:

var arr = []

Then later when you want to append new elements use push like this:

arr.push( Math.floor(Math.random()*10) )

adding html using innerHTML

There are different ways to dynamically inject html into your page. (It looks like) you tried to append the html as a string to the parent element. This is not possible.

You said you tried using innerHTML. That should work if used correctly.

A working implementation would work like this:

function start() {
 var arr = []
 var result = "<p>"
 for(var i = 0; i < 5; i++) {
  arr.push( Math.floor(Math.random()*10) ) // Btw this array isn't actually needed.
  result += "arr[" + i + "] = " + arr[i] + "</p><p>"
 }
 document.getElementById("arraying").innerHTML = result
}
window.addEventListener("load", start, {passive: true});

adding html using createElement

A generally better way of dynamically adding html elements is via createElement.

This way you dont have to write html and are therefore less prone for making errors. It is also more performant and easier to integrate into javascript.

I think the best explaination is a commented implementation:

function start() {
 var myDiv = document.getElementById("arraying") // get parent node
 var arr = []
 for(var i = 0; i < 5; i++) {
  arr.push( Math.floor(Math.random()*10) )
  var p = document.createElement("p") // create p element
  p.innerText = "arr[" + i + "] = " + arr[i] // add text content to p element
  myDiv.append(p) // append p element to parent element
 }
}
window.addEventListener("load", start, {passive: true});

small tips

The let keyword works mostly the same as the var keyword, but is generally preferred because of some edge cases in which let is superior.

Fusing strings and variables using the plus operator is generally considered bad practice. A better way to do the string concatenation would have been

result += `arr[${i}] = ${arr[i]}</p><p>`
about 4 years ago · Juan Pablo Isaza Report
Answer question
Find remote jobs

Discover the new way to find a job!

Top jobs
Top job categories
Business
Post vacancy Pricing Sales
Legal
Terms and conditions Privacy policy
© 2026 PeakU Inc. All Rights Reserved.
Andres GPT
Show me some job opportunities
There's an error!