I have an array res with some nullish values, and I have a function remove that is supposed return an array with nulls and undefined removed, but I can't get it to work on my array. I've seen plenty of answers on this sort of thing, in fact my remove function originated from one of them, but I can't seem to get it to work.
res =
[
{
"1yKKftO0iOyvsacrW1mEr-FylurU8-fwaefewafw": [
"raggy@champ.co",
"grope@champ.co",
null,
"halp@champ.co"
]
},
{
"149Lmt-gweagewfrthjregjiojoinONEDOnonao": [
"raggy@champ.co"
]
},
{
"JG043AHF0GJA0EWJIFJO00WIJF-UffFWEAk8QRg4": [
"wlyman@champ.co",
"raggy@champ.co"
]
},
{
"1u-Frw5I4agI-FWKE0AFJ0WEJG0JEFDALKFEWA-ns": [
null,
"raggy@champ.co"
]
},
{
"FAWGETAIODIOFAIJDSOIFJWEOFijewaofifejowef": [
"raggy@champ.co"
]
},
{
"fwaejf0JF0EWJIJFFJMojfeoijfewJEJFI0i0fje": [
"raggy@champ.co"
]
},
{
"FJ09Ejf093ejfie0jfeiJFEJF0IWJFEIJFOEJWow": [
"raggy@champ.co"
]
}
]
var remove = function (array) {
var result = [];
array.forEach(function (item) {
if (Array.isArray(item) && item.length!=0) {
// Item is a nested array, go one level deeper recursively
result.push(remove(item));
}
else if (typeof item !== null) {
result.push(item);
}
});
return result;
};
console.log(remove(res));
Here is a solution without recursion that will work for the nesting level given in example. Also will work if a single array element has multiple key value pairs.
let res =[{"1yKKftO0iOyvsacrW1mEr-FylurU8-fwaefewafw": ["raggy@champ.co","grope@champ.co",null,"halp@champ.co"]},{"149Lmt-gweagewfrthjregjiojoinONEDOnonao": ["raggy@champ.co"]},{"JG043AHF0GJA0EWJIFJO00WIJF-UffFWEAk8QRg4": ["wlyman@champ.co","raggy@champ.co"]},{"1u-Frw5I4agI-FWKE0AFJ0WEJG0JEFDALKFEWA-ns": [undefined,"raggy@champ.co"]},{"FAWGETAIODIOFAIJDSOIFJWEOFijewaofifejowef": ["raggy@champ.co"]},{"fwaejf0JF0EWJIJFFJMojfeoijfewJEJFI0i0fje": ["raggy@champ.co"]},{"FJ09Ejf093ejfie0jfeiJFEJF0IWJFEIJFOEJWow": ["raggy@champ.co",null]}]
var remove = function (array) {
return array.map(function (item) {
let x = Object.entries(item).map((y) => {
return [y[0],y[1].filter((z)=> z!==undefined && z!==null)]
})
return Object.fromEntries(x)
});
};
console.log(remove(res));If you want to remove nulls as well as undefineds, you probably want to replace else if (typeof item !== null) with else if (typeof item != null)
The elements of res are Objects.
Notice that in the nested function call of remove
result.push(remove(item));
the item being passed are elements of res thus not an array. So when remove(item) is called the check Array.isArray(item) fails and nothing is sorted out.
To get the inner array make add this line.
var values = Object.values(item)
Now handle the cases of item being null, Object and Array.
Here's my Attempt at the solution. (I hope you don't mind ES6) This does work on this particular (not sure about other cases)
const remove = (item) => {
if (item) {
console.log('not null', item)
if (Array.isArray(item)) {
const result = []
for (let elem of item) {
const cleanedElem = remove(elem)
// Maybe use Nullish coalescing operator ?
if (cleanedElem !== null && cleanedElem !== undefined)
result.push(cleanedElem)
}
return result
} else if (typeof item === 'string' || typeof item === 'number') {
return item
} else if (item) {
const result = {}
for (let pair of Object.entries(item)) {
const [key, value] = pair
const cleanedValue = remove(value)
// Maybe use Nullish coalescing operator ?
if (cleanedValue !== null && cleanedValue !== undefined)
result[key] = remove(cleanedValue)
}
return result
}
}
}
cleansed = remove(res)
console.log(cleansed);