Sorry for making a post with a generic error but I just can't figure this out! I have an ajax call that for now sends an empty object and just returns json_encode(array('status' => 'success')); while I'm debugging. The ajax call is failing with Error in ajax call. Error: SyntaxError: Unexpected end of JSON input
I've tried sending just data['pid']='csv' in case the json needed to have something in it, but still get the same error.
AJAX call
function runDataDownload() {
var data = {};
// data['rawFiles'] = $('#projectIDs').val();
// data['metadata'] = $('#getData').val();
// data['type']= $('#submitType').val();
// data['pid']='csv';
// data['command']='data/qcTest';
console.log(data);
console.log(typeof data)
var qcRunId="csv" + Date.now();
var posturl = baseURL + "manage/ajax_runBg/csv/" + qcRunId;
$.ajax({type: "POST", url: posturl, data: data, dataType: 'json'})
.done(function(result) {
console.log(result);
if (result.status==='success'){
// begin checking on progress
checkRunStatus(qcRunId, loopIndex);
}
else if (result.status==='failed'){
$('#' + errorId + ' > li').remove();
$.each(result.errors, function(key, value) {
$('#' + errorId).append( "<li>" + value + "</li>" );
});
$('#' + statusId).hide();
$('#' + errorId).show();
}
else {
$('#' + errorId + ' > li').remove();
$('#' + errorId).append( "<li>Invalid return from ajax call</li>" );
$('#' + errorId).show();
// PTODO - may not be needed
// make sure it is visible
$('#' + errorId).get(0).scrollIntoView();
}
})
.fail(function(jqXHR, status, err) {
console.log(jqXHR + status + err);
$('#' + errorId + ' > li').remove();
$('#' + errorId).append( `<li>Error in ajax call. Error: ${status} (${err.name}: ${err.message})</li>`);
$('#' + errorId).show();
});
}
And my php code:
public function ajax_runBg($qcName, $runId) {
echo json_encode(array('status' => 'success'));
}
Thank you!
Something seems to clear the PHP output buffer after ajax_runBg has been called. Check this by adding ob_flush(); flush(); to ajax_runBg after the echo statement.
Sorry for making an answer, when i don't have a full one, I don't have enough reputation to comment.
I ran this code (i removed variables that i don't have) and did not get an error (nothing wrong with "echo json_encode(array('status' => 'success'));").
Here are some possible reasons why it fails: Your problem could be that the php does not echo anything.
I once got this problem and fixed it by first making a variable out of json_encode("stuff to encode") and then doing echo on that variable.
Is there more to the php file that you did not show? There could be a problem if there are other things being echoed.
When sending json you must first encode it as json, so:
$.ajax({type: "POST", url: posturl, data: JSON.stringify(data), dataType: 'json'})