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Encontrar duplicados en una matriz de objetos en javascipt por método de mapa

Estoy tratando de eliminar el duplicado de una matriz de objetos en Javascript. A continuación se muestra el código que no funciona, está creando una matriz de mapa de tamaño 4.

 let arr = [{id: 32, name: 'Name1', age: 88}, {id: 33, name: 'Name2', age: 88}, {id: 32, name: 'Name3', age: 88}, {id: 1, name: 'Sam', age: 88}, {id: 33, name: 'Name2', age: 88}, {id: 2, name: 'Tom', age: 88} ]; console.log(arr) let mp1 = new Map(); let uniqueElements = arr.map( obj => mp1.set(obj.id, obj)) console.log(uniqueElements);

about 4 years ago · Juan Pablo Isaza
2 answers
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0

El siguiente fragmento puede ser una posible implementación para lograr el objetivo deseado:

 const discardDupeIdElements = arr => ( Object.values( arr.reduce( (fin, itm) => ({ ...fin, [itm.id]: itm }), {} ) ) ); var origArr = [{ id: 32, name: 'Name1', age: 88 }, { id: 33, name: 'Name2', age: 88 }, { id: 32, name: 'Name3', age: 88 }, { id: 1, name: 'Sam', age: 88 }, { id: 33, name: 'Name2', age: 88 }, { id: 2, name: 'Tom', age: 88 } ]; console.log(discardDupeIdElements(origArr));

Nota

Esto siempre mantendrá el last elemento de un conjunto de duplicados e ignorará todos los anteriores. Como para id 32, mantendrá el elemento con name = Name3 y descartará Name2 .

Arreglando el código del OP :

 const arr = [{id: 32, name: 'Name1', age: 88}, {id: 33, name: 'Name2', age: 88}, {id: 32, name: 'Name3', age: 88}, {id: 1, name: 'Sam', age: 88}, {id: 33, name: 'Name2', age: 88}, {id: 2, name: 'Tom', age: 88} ]; // console.log(arr); // commented-out for easier viewing of the output const mp1 = new Map(); // declared a map arr.forEach(obj => mp1.set(obj.id, obj)); // used .forEach to iterate through the array // and update the map const uniqueElements = [...mp1.values()]; // used spread operator to extract // the values of the map into an array console.log(uniqueElements); // console.log the unique elements

Nota

Siempre que sea posible, use const en lugar de let .

about 4 years ago · Juan Pablo Isaza Report

0

map devuelve la nueva matriz con la misma longitud de la matriz de llamada

Para el valor acumulado (aquí está mp1 ), debe usar reduce

 let uniqueElements = arr.reduce( (mp1, obj) => mp1.set(obj.id, obj), new Map() ) 

 let arr = [ { id: 32, name: 'Name1', age: 88 }, { id: 33, name: 'Name2', age: 88 }, { id: 32, name: 'Name3', age: 88 }, { id: 1, name: 'Sam', age: 88 }, { id: 33, name: 'Name2', age: 88 }, { id: 2, name: 'Tom', age: 88 }, ] console.log(arr) let uniqueElements = arr.reduce((mp1, obj) => mp1.set(obj.id, obj), new Map()) console.log(uniqueElements)

about 4 years ago · Juan Pablo Isaza Report
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