Sorting this array of objects works if I map the objects first:
let data = [{
"date": "2018-07-31T00:00:00Z"
}, {
date: undefined
}, {
"date": "2020-07-01T00:00:00Z"
}, {
"date": "2019-08-24T11:16:26Z"
}, {
"date": "2011-11-19T00:00:00Z"
}]
let compare = (a, b) => {
if (a < b) return 1;
if (a > b) return -1;
return 0
}
// Note: Use map first
let result = data.map(x=>x.date);
console.log(result.sort(compare))But if I sort this array without mapping the objects first, sort doesn't work:
let data = [{
"date": "2018-07-31T00:00:00Z"
}, {
date: undefined
}, {
"date": "2020-07-01T00:00:00Z"
}, {
"date": "2019-08-24T11:16:26Z"
}, {
"date": "2011-11-19T00:00:00Z"
}]
// Similar compare function just adapted
let compare = (a, b) => {
if (a.date < b.date) return 1;
if (a.date > b.date) return -1;
return 0
}
// Note: No map
let result = data;
console.log(result.sort(compare))I can't see why this happens?
The problem is the object where the date is undefined. In the first example (with .map()), all the values are either strings or the one undefined. As per the specification of Array.prototype.sort():
"all undefined elements are sorted to the end of the array, with no call to compareFunction"
(MDN)
In the first example, the function is never called for the undefined value, so it is sorted last. In the second example, however, whenever you get a.date on the undefined value, you get undefined. Both if statements in the sort function then resolve to false since undefined can't be less than or greater than a string. Therefore, 0 is continually returned for the following elements. The undefined remains in place and breaks the rest of the sorting.