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Return array and function that returns another array together JS

I'm currently trying to return an array with some values and a function that returns another array as well. How do I do it that my returns is basically 2 arrays instead of 1 array and 1 function

Example

const array1 = [a, b, c]

const function = () => {
  if(something) {
    somevalues.map(e => {
      return ( 
        <div>{e}<div>
     )
   })
  } else {
    othervalues.map(f => {
      return ( 
        <div>{f}<div>
     )
   })
  }
} 

return [...array1, function] ??

function in the example obviously returns function instead of its own return, how do I fix that?

about 4 years ago · Juan Pablo Isaza

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const array1 = ['a', 'b', 'c'];
const something = true;

const func = () => {
  if(something) {
    return 'e';
  } else {
    return 'f';
  }
};

console.log([...array1, func()]); //[ "a", "b", "c", "e" ]

about 4 years ago · Juan Pablo Isaza Report

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Accepted Answer · 2022-07-03T18:22:17.892Z

You need to

actually return something from your function. If you don't return the return values of somevalues.map(...) and othervalues.map(...) then your function will return undefined.
call the function to get its return value
spread the return value into the result array, just like you do with the static array.

Example:

const array1 = [a, b, c]

const outerFunction = () => {

  const innerFunction = () => {
    if(something) {
      return somevalues.map(e => (<div>{e}<div>));
//    ^^^^^^
    } else {
      return othervalues.map(f => (<div>{f}<div>));
//    ^^^^^^
    }
  } 

  return [...array1, ...innerFunction()];
//                   ^^^             ^^
}

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Return array and function that returns another array together JS

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Andres GPT