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change even character in string with the for loop

hello everyone please i'am a begginer in javascript and i found this challenge , but i don't know how to solve it

let str1 = "javascript";  

// Example output: 
// jZvZsZrZpZ OR each letter on a new line
// HINT: You can use  if((i+1) % 2 == 0) to check for even indexes 

for (let i = 0; i < str1.length; i++) {
if ((i + 1) % 2 === 0) {
    str1[i].replace(str1[i],"z")
}
}

can you explain this for me please i try this soltuion but it doesn't work

about 4 years ago · Juan Pablo Isaza

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Answer 1 · 2022-07-03T19:45:41.938Z

This should work for you. JsFidle

let str1 = "javascript";  

const res = [...str1].map((letter, index)=>{
 return index % 2 != 0 ? "Z" : letter
})

console.log(res.join(""))

Answer 2 · 2022-07-03T19:45:41.953Z

let str1 = "javascript";  
// Example output: 
// jZvZsZrZpZ OR each letter on a new line
var a = str1.split("");
let replaceChar = function(char){
for(let i=1;i<str1.length;i++){
    if((i+1)% 2 === 0)
     a[i] = char
    }
 return a.join("");
}
console.log( replaceChar("Z"))

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change even character in string with the for loop

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Andres GPT