var guestList = ['Gabe', 'name2', 'name3', 'name4', 'name5']
var guestName = prompt('Hello, what is your name')
var range = guestList.slice(0, guestList.length)
if (guestList.includes(range)) {
alert(`Hello ${guestName} and welcome to EVENT NAME`)
} else {
alert(`Hello ${guestName}, you are not on the guest list`)
}Take a look on that line of your code var range = guestList.slice(0, guestList.length). Now range is a sub-array of guestList and you´re trying to verifacate in guestListif it includes the element range that is not true.
I think you´re trying to do this:
var guestList = ['Gabe', 'name2', 'name3', 'name4', 'name5']
var guestName = prompt('Hello, what is your name')
if (guestList.includes(guestName)) {
alert(`Hello ${guestName} and welcome to EVENT NAME`)
} else {
alert(`Hello ${guestName}, you are not on the guest list`)
}Remove range because it's useless and replace range in this line with guestName
if (guestList.includes(guestName)) {....
Prompt() returns a value which is whatever the user entered.
var guestList = ['Gabe', 'name2', 'name3', 'name4', 'name5']
var guestName = prompt('Hello, what is your name')
/* Add this line if you want the comparison
to be case insensitive
*/
// guestList = guestList.map(name => name.toLowerCase());
/* And replace guestName with
guestName.toLowerCase() in the "if"
statement as well.
*/
if (guestList.includes(guestName)) {
alert(`Hello ${guestName} and welcome to EVENT NAME`)
} else {
alert(`Hello ${guestName}, you are not on the guest list`);
}Is this what you want?
var guestList = ['Gabe', 'name2', 'name3', 'name4', 'name5']
var guestName = prompt('Hello, what is your name')
if (guestList.includes(guestName)) {
alert(`Hello ${guestName} and welcome to EVENT NAME`)
} else {
alert(`Hello ${guestName}, you are not on the guest list`)
}