Given an array [1, 2, 2, 3, 4, 4, 5], is it possible to shuffle the array while preventing the duplicates to be next to each other?
For example:
[1, 2, 3, 4, 2, 5, 4] is an acceptable solution.[1, 2, 3, 4, 4, 2, 5] is not an acceptable solution since 4 is next to another 4This seems like a simple question but after thinking about it, the solution seems complicated. Any help is greatly appreciated, thanks!!
If you don't care about the execution time of the algorithm, just shuffle a few times until you get the result you want
let arr = [1, 2, 2, 3, 4, 4, 5];
const hasDublicateItems = (arr) => arr.some((v, i, a) => v === a[i+1]);
while (hasDublicateItems(arr))
arr = arr.sort(() => (Math.random() > .5) ? 1 : -1);
console.log(arr);
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