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Compruebe si la propiedad en cada elemento de la matriz no es nula

Dado el siguiente objeto, ¿cómo puedo saber si todos los empleados tienen un valor no nulo para la propiedad SSN?

 Employees: { id: 0, name: "John", SSN: "1234" } { id: 1, name: "Mark", SSN: "1876" } { id: 2, name: "Sue", SSN: "98826" }
about 4 years ago · Juan Pablo Isaza
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Suponiendo que 0 no es un SSN válido, puede usar Number(Employees[i].SSN) > 0 para tomar esa determinación:

Parque infantil TS

 const Employees = [ { id: 0, name: "A", SSN: "1234" }, // true { id: 1, name: "B", SSN: "1876" }, // true { id: 2, name: "C", SSN: "" }, // false { id: 3, name: "D", SSN: null }, // false { id: 4, name: "E", SSN: undefined }, // false { id: 5, name: "F" }, // false { id: 6, name: "G", SSN: "98826" }, // true ]; function hasSSN <T extends {SSN?: string | null | undefined}>(value: T): value is T & {SSN: string} { return Number(value.SSN) > 0; } for (const employee of Employees) { console.log(employee.name, hasSSN(employee)); }

Manifestación:

 const Employees = [ { id: 0, name: "A", SSN: "1234" }, { id: 1, name: "B", SSN: "1876" }, { id: 2, name: "C", SSN: "" }, { id: 3, name: "D", SSN: null }, { id: 4, name: "E", SSN: undefined }, { id: 5, name: "F" }, { id: 6, name: "G", SSN: "98826" }, // true ]; function hasSSN(value) { return Number(value.SSN) > 0; } for (const employee of Employees) { console.log(employee.name, hasSSN(employee)); }

about 4 years ago · Juan Pablo Isaza Report
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