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Fácil AJAX, MySQL y PHP

Estoy tratando de hacer que este ejemplo funcione. Aquí está mi HTML como familyguy.html.

 <html> <head> <script> function showUser(str) { if (str == "") { document.getElementById("txtHint").innerHTML = ""; return; } else { var xmlhttp = new XMLHttpRequest(); xmlhttp.onreadystatechange = function() { if (this.readyState == 4 && this.status == 200) { document.getElementById("txtHint").innerHTML = this.responseText; } }; xmlhttp.open("GET","getuser.php?q="+str,true); xmlhttp.send(); } } </script> </head> <body> <form> <select name="users" onchange="showUser(this.value)"> <option value="">Select a person:</option> <option value="1">Peter Griffin</option> <option value="2">Lois Griffin</option> <option value="3">Joseph Swanson</option> <option value="4">Glenn Quagmire</option> </select> </form> <br> <div id="txtHint"><b>Person info will be listed here...</b></div> </body> </html>
Y aquí está mi código php getuser.php.

Creé la base de datos stuff_data y la llené con 4 filas. Mi lista desplegable no hace nada. Por favor ayuda.

Gracias.

Neo

about 4 years ago · Juan Pablo Isaza
1 answers
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Cambié el campo de host a localhost y esto resolvió el problema.

about 4 years ago · Juan Pablo Isaza Report
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