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Obtener información innecesaria de la consulta de MongoDB usando mongoose

Estoy usando mongoose para consultar una base de datos local y lo he intentado: (Suponga que cardName está definido)

const card = await Card.findOne({ name: cardName }, 'name art description')

const card = await Card.findOne({ name: cardName }, { name: 1,art: 1,description: 1 })

const card = await Card.findOne({ name: cardName }).project('name art description')

const card = await Card.findOne({ name: cardName }, 'name art description').exec()

Aunque obtengo los campos que especifico, también obtengo otros campos innecesarios, como

 $__schema: [object Object] collection: [object Object] $collection: [object Object] $__originalValidate: function(pathsToValidate, options, callback) { if (typeof pathsToValid . . . $__save: function() { var _context = context || this; _this.wrap(name, fn, _context, Array.from(arguments), options); } $__validate: function() { var _context = context || this; _this.wrap(name, fn, _context, Array.from(arguments), options); } $__remove: function() { var _context = context || this; _this.wrap(name, fn, _context, Array.from(arguments), options); } $__deleteOne: function() { process.nextTick(() => fn.apply(this, arguments)); } $__init: function syncWrapper() { kareem.execPreSync(name, this, arguments); var toReturn = fn.apply(this, arguments); kareem.execPostSync(name, this, [toReturn]); return toReturn; } $isMongooseModelPrototype: true $__handleSave: function(options, callback) . . .

¿Cómo me aseguro de obtener solo los campos que especifico y NO la información innecesaria?

about 4 years ago · Juan Pablo Isaza
1 answers
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Puede usar la función lean() en su consulta. De los documentos:

Los documentos devueltos por consultas con la opción Lean habilitada son objetos simples de JavaScript, no documentos Mongoose. No tienen método de guardado, getters/setters, virtuales u otras características de Mongoose.

 const docs = await Model.find().lean();
about 4 years ago · Juan Pablo Isaza Report
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