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what is the difference between these two usages of wrapper function?

These two usages below seem work fine:

  1. wrapper function without return

document.querySelector(`button`).addEventListener(`click`, delayedClickButton);

const timeout = 1000;
function delayedClickButton(evt) {
  setTimeout(
      function (){clickButton(evt)},
      timeout
    );
}

function clickButton(evt) {
  evt.target.style.color = `red`;
}
<button>Click</button>

  1. wrapper function with return

document.querySelector(`button`).addEventListener(`click`, delayedClickButton);

const timeout = 1000;
function delayedClickButton(evt) {
  setTimeout(
      function (){return clickButton(evt);},
      timeout
    );
}

function clickButton(evt) {
  evt.target.style.color = `red`;
}
<button>Click</button>

Which one is correct when I want a click event handling function that is delayed for 1 second, and I want to access the target element in that function by using evt.target.

about 4 years ago · Juan Pablo Isaza
1 answers
Answer question

0

The return statement isn't needed so the first example is better, although they both work. returns are useful for when we want to do something with a resulting value e.g.

const myFunc = ()=>{
  return 'I returned something'
}

console.log(myFunc())

about 4 years ago · Juan Pablo Isaza Report
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