everything good? I would like some help from you, I have the following scenario:
STRING_ONE:
string_two
STRING_three :
string_four:
stringfive:
I need to identify words from the beginning of the line that end with :
after identifying the words, I need to erase the spaces and convert them to uppercase, i tried doing some regex but as the words change I can't set the default for the replacement because i need to keep the same word, just removing the spaces and converting to capital letters
The result I'm trying to get is this:
STRING_ONE:
string_two
STRING_three :
STRING_FOUR:
STRINGFIVE:
I can capture the words that match this pattern, with the following regex, but I don't know how to replace it by just erasing the spaces, keeping the rest of the string the same, and doing the upper case
^.*\b:
I tried to replace like this but it didn't work
"$1".toUpperCase()
Can anyone help please? Thanks!
As you are not really replacing anything but instead you are looking for a pattern I used the pattern in a String.prototype.match() to identify the lines in which .trim() and .toLowerCase() need to be applied. The .split("\n") turns the initial string into an array over which I can then .map() the individual lines. At the end I .join() everything together again.
const str=`STRING_ONE:
string_two
STRING_three :
string_four:
stringfive:`;
console.log(str
.split("\n")
.map(s=>s.match(/^\s*\w+:\s*$/) && s.trim().toUpperCase() || s )
.join("\n")
);Our regex patterns differ slightly:
/^.*\b:/) will match any line that has at least one word-end followed by a colon in it/^\s*\w+:\s*$/) is stricter and demands that there is exactly one word followed by a colon in a line that can optionally be padded by any number of whitespace characters on either side.