i want to check i an array contains the elements of any sub array, i.e.
array1 = [10,11,12]
array 2 = [[10, 11],[20, 21],[30, 31],[40, 41]];
array1 will be checked in series by each of array2's sub arrays and if the sub array elements are also in the array1 then to return true.
i've tried thing like:
array2.some((arr) => {
return arr.every((square) => {
return array1.includes(square);
});
});
or
for (let elem of array2) {
if (elem.every((x) => array1.includes(x))) {
return false;
} else {
return true;
}
}
any advice would be helpfull. thank you
You need to iterate the sub array as well for the sequence.
const
array1 = [10, 11, 12],
array2 = [[10, 11], [20, 21], [30, 31], [40, 41]],
result = array2.some(a => {
for (let i = 0, l = array1.length - 1; i < l; i++) {
if (a.every((v, j) => v === array1[i + j])) return true;
}
return false;
});
console.log(result);