here is a sample example where there are two arrays and we have a merge() to which we pass the arrays. the merge() should return the merged array such that it should merge the objects which have same name.
let arr1 = [
{
name: "Person1",
age: 20
},
{
name: "Person2",
age: 30
}
]
let arr2 = [
{
name: "Person1",
email: "person1@mail.com"
},
{
name: "Person3",
age: 25
}
]
arr3 = merge(arr1, arr2)
output :
arr3 should be :
[
{
name: "Person1",
age: 20,
email: "person1@mail.com"
},
{
name: "Person2",
age: 30
},
{
name: "Person3",
age: 25
}
]
You could take an object as hash table for keeping track of merged objects with same name and return only the values from the hash table.
const
merge = (...arrays) => {
const merged = {};
arrays.forEach(data =>
data.forEach(o => Object.assign(merged[o.name] ??= {}, o))
);
return Object.values(merged);
},
array1 = [{ name: "Person1", age: 20 }, { name: "Person2", age: 30 }],
array2 = [{name: "Person1", email: "person1@mail.com" }, { name: "Person3", age: 25 }],
result = merge(array1, array2);
console.log(result);.as-console-wrapper { max-height: 100% !important; top: 0; }You can use lodash for that
let arr1 = [
{
name: "Person1",
age: 20
},
{
name: "Person2",
age: 30
}
]
let arr2 = [
{
name: "Person1",
email: "person1@mail.com"
},
{
name: "Person3",
age: 25
}
]
arr3 = _.merge(_.keyBy(arr1, 'name'), _.keyBy(arr2, 'name'));
console.log(arr3)<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.15/lodash.min.js"></script>The map part covers every item in arr1, so you can add it as is or merge with the ones both in arr1 and arr2. Then you need a final pass to add those that are in arr2 but not in arr1
let arr1 = [
{
name: "Person1",
age: 20
},
{
name: "Person2",
age: 30
}
]
let arr2 = [
{
name: "Person1",
email: "person1@mail.com"
},
{
name: "Person3",
age: 25
}
]
const merge = (a1,a2) => {
return a1.map( (x) => {
const y = a2.find( item => x.name === item.name);
if (y) {
return Object.assign({},x,y);
} else
return x
}).concat(a2.filter(item => a1.every( x => x.name !== item.name)));
}
arr3 = merge(arr1, arr2)
console.log(arr3)