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How to handle mutation GraphQL error instead of Apollo onError()

Server side, I am throwing a 403 Forbidden, to manage access to an API call.

To catch the GraphQL error for a mutation, I've tried the following: (method #1 is working when catching errors for useQuery())

const [m, { error }] = useMutation(MY_MUTATION);

if(error) {
    console.error('Error return #1');
}

try {
  await m({
    variables,
    onError: (e: ApolloError) => {
       console.error('Error return #2');
    }
  }).catch(e) {
     console.error('Error return #3');
  };
} catch (e) {
    console.error('Error return #4');
}

Instead, from my Apollo onError(), the following GraphQL errors are returned and the execution stops. It does not go into any of my mutation error handling attempts:

graphQLErrors:, Array [
  Object {
    "extensions": Object {
      "code": "FORBIDDEN",
      "response": Object {
        "error": "Forbidden",
        "message": "Access is denied.",
        "statusCode": 403,
      },
    },
    "message": "Access is denied.",
  },
]

If a similar GraphQL error is returned from useQuery(), it shows it using:

const { data, error, loading } = useQuery( MY_QUERY );

if(error) {
    console.error('Error return #1');
}
about 4 years ago · Juan Pablo Isaza
1 answers
Answer question

0

Based on useMutation documentation I believe mutate (or m) function doesn't accept onError callback and you have to set it in useMutation options.

const [m, { error }] = useMutation(MY_MUTATION, {
  onError: (e: ApolloError) => {
     console.error('Error return #2');
  }
});

if (error) {
    console.error('Error return #1');
}

try {
  await m({
    variables
  })
} catch (e) {
    console.error('Error return #4');
}
about 4 years ago · Juan Pablo Isaza Report
Answer question
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