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¿Cómo podemos pasar el argumento a la función que a su vez se pasa como argumento en javascript?
function fun (a, b) { console.log(a + ' ' + b); return a == b; } function test(condition) { for(let i = 0; i < 1; i++) { if(condition()){ break; } } }

¿Cómo podemos pasar la función fun como argumento dentro de la función test con el argumento a y b (a y b son variables)? test(fun('a', 'b')); está dando como resultado un error.

about 4 years ago · Juan Pablo Isaza
1 answers
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0

Puedes usar un closure como este:

 test(function(){ return fun('a', 'b'); });
about 4 years ago · Juan Pablo Isaza Report
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