I want my users to enter their birth year. I don't want them to type the same in the form rather select the year from available options. I known that I can do something like this in my model if I needed to date instead of year:
class MyModel(models.Model):
birthday = models.DateField(null=True, blank=True)
I can do this in forms to let the user choose date from datepicker.
birthday = forms.fields.DateField(widget=forms.widgets.DateInput(attrs={'type': 'date'}))
For year, I can use a CharField/IntegerField with choices similar to what has been done in this SO answer.
import datetime
YEAR_CHOICES = [(r,r) for r in range(1984, datetime.date.today().year+1)]
year = models.IntegerField(_('year'), choices=YEAR_CHOICES, default=datetime.datetime.now().year)
The problem, however, is that change of current year from say, 2018 to 2019, will not change the available options.
Can you help or provide hints to achieve what I want to do?
Santiago Trujillo
My initial thought was to write a callable that returns the choices, that will be evaluated for each request.
import datetime
def year_choices():
return [(r,r) for r in range(1984, datetime.date.today().year+1)]
def current_year():
return datetime.date.today().year
class MyModel(models.Model):
year = models.IntegerField(_('year'), choices=year_choices, default=current_year)
However this doesn't work, because Django's check framework doesn't allow the year_choices to be used as the default. Even if you could hack the choices to be generated dynamically, it would have the disadvantage that Django would try to create a migration each year when the choices change.
You can avoid this by generating the choices at the form level instead. You can use validators in the model to prevent invalid data. Note that MaxValueValidator is wrapped in a function max_value_current_year to avoid a new migration every year.
import datetime
from django.core.validators import MaxValueValidator, MinValueValidator
def current_year():
return datetime.date.today().year
def max_value_current_year(value):
return MaxValueValidator(current_year())(value)
class MyModel(models.Model):
year = models.IntegerField(_('year'), validators=[MinValueValidator(1984), max_value_current_year])
def year_choices():
return [(r,r) for r in range(1984, datetime.date.today().year+1)]
class MyForm(forms.ModelForm):
year = forms.TypedChoiceField(coerce=int, choices=year_choices, initial=current_year)
You can put the options(years) in the form, using the IntegerField min_value and max_value. In model you can use the IntegerField without choices.
So, you won't worry about when the year change, because you will only change the options in the form.
If you want to change the year automatically, this could help you: Django forms integerField set max_value on runtime
For those who don't prefer having long choice fields i.e. in @Alasdair solution imagine having a choice field from 1984 to 2019, such a long choice list. How about having a field you can type the year and still have a way to increment or decrements. To solve this my way, use models.PositiveIntegerField with MinValueValidator and MaxValueValidator as shown below:
import datetime
from django.core.validators import MaxValueValidator, MinValueValidator
from django.db import models
def current_year():
return datetime.date.today().year
def max_value_current_year(value):
return MaxValueValidator(current_year())(value)
class EmployeesTrainings(models.Model):
name = models.ForeignKey(employee, default='', blank=True, null=True, on_delete=models.CASCADE)
training_name = models.TextField(max_length=200, default='', blank=False, null=False)
training_year = models.PositiveIntegerField(
default=current_year(), validators=[MinValueValidator(1984), max_value_current_year])