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Buscar dentro de un Javascript JSON

Tengo un problema relacionado con la búsqueda de una cadena JSON y tengo una cadena JSON

 {"userDetail":[ { "Name": "Scottic Mangry", "Age" : "12", }, { "Name": "Joneson Mangly", "Age" : "18", }, { "Name": "Saoyu Wang", "Age" : "15", }, ]}

y búsqueda de datos

 let searchObj = "Mang"

necesito un resultado

 { "Name": "Scottic Mangry", "Age" : "12", }, { "Name": "Joneson Mangly", "Age" : "18", }

¡Cualquier ayuda o sugerencia sería genial!

about 4 years ago · Juan Pablo Isaza
3 answers
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0

Algo como:

 let data = { "userDetail":[ { "Name": "Scottic Mangry", "Age" : "12", }, { "Name": "Joneson Mangly", "Age" : "18", }, { "Name": "Saoyu Wang", "Age" : "15", }, ] } let needle = "Mang"; let result = data['userDetail'].filter(el => el.Name.includes(needle)); console.log(result);

needle es la cadena que estamos buscando dentro de la propiedad Name del objeto data.userDetail

includes distingue entre mayúsculas y minúsculas, por lo que si desea hacer coincidir los resultados independientemente de las mayúsculas y minúsculas, es más fácil poner todo en minúsculas primero

about 4 years ago · Juan Pablo Isaza Report

0

puedes hacerlo usando Array.filter , Array.values e includes

 const data = {"userDetail":[ { "Name": "Scottic Mangry", "Age" : "12", }, { "Name": "Joneson Mangly", "Age" : "18", }, { "Name": "Saoyu Wang", "Age" : "15", }, ]} const search = (data, search) => data.filter(d => Object.values(d).some(v => v.includes(search))) console.log(search(data.userDetail, "Mang"))

about 4 years ago · Juan Pablo Isaza Report

0

Como dice cmgchess en los comentarios, el uso de filtros e inclusiones haría el trabajo por usted: para hacerlo más declarativo y legible, lo puse dentro de una función llamada findName

 const objs = { "userDetail": [{ "Name": "Scottic Mangry", "Age": "12", }, { "Name": "Joneson Mangly", "Age": "18", }, { "Name": "Saoyu Wang", "Age": "15", }, ] } function findName(name) { return objs.userDetail.filter(user => user.Name.includes(name)) } let searchObj = "Mang"; console.log(findName(searchObj));

about 4 years ago · Juan Pablo Isaza Report
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