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Factorización de una función usando un forEach-loop

Me gustaría escribir un código más corto para find usando .forEach pero encontré problemas con el conteo y el return no funciona:

 function find(array, element) { array.forEach((_, i) => { if (array[i] === element) { return i; } }) return "Not found"; } 

 let array = [2,3,5,7,11]; function find(array, element) { for (let i = 0; i < array.length; i++) { console.log(i) if (array[i] === element) { return i; } } return "Not found"; } console.log(find(array, 5)) //2 console.log(find(array, 12)) //Not found

almost 3 years ago · Juan Pablo Isaza
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0

let matriz = [2,3,5,7,11];

función encontrar (matriz, elemento) {

 let index = array.indexOf(element) != -1 ? array.indexOf(element) : "Not Found"; return index;

}

consola.log(buscar(matriz, 5))

consola.log(buscar(matriz, 12))

almost 3 years ago · Juan Pablo Isaza Report

0

return no va a funcionar dentro de un forEach. Le sugiero que use la función de filtro en su lugar. pero si insiste en usar forEach, puede usar este código como muestra.

 function find(array, element) { let result="not found"; array.forEach((arrayItem, i) => { if (arrayItem === element) { result = i; } }) return result; }
almost 3 years ago · Juan Pablo Isaza Report
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