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la lógica aquí no tiene sentido en javascript

 cellColor = {}; cellColor['cel32'] = 'blue'; cellColor['cel24'] = 'blue'; cellColor['cel16'] = 'blue'; cellColor['cel8'] = 'blue'; console.log( (((cellColor['cel32'] === cellColor['cel24']) === cellColor['cel16']) == cellColor['cel8']) == 'blue', );

// la salida es falsa aquí ¿por qué?

about 4 years ago · Santiago Gelvez
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Está comparando boolean con blue , por lo que devolverá false

está comparando true con blue , que devolverá false .

 cellColor = {}; cellColor['cel32'] = 'blue'; cellColor['cel24'] = 'blue'; cellColor['cel16'] = 'blue'; cellColor['cel8'] = 'blue'; const a = cellColor['cel32'] === cellColor['cel24']; console.log(a); // true const b = cellColor['cel16']; // Here a is true and b is blue const c = a === b; console.log(c); // true is not equal to 'blue' so return false // Here c is false and cellColor['cel8'] is blue const d = c === cellColor['cel8']; console.log(d); // false is not equal to 'blue' so return false const e = d === 'blue'; console.log(e);// false is not equal to 'blue' so return false 

 cellColor = {}; cellColor['cel32'] = 'blue'; cellColor['cel24'] = 'blue'; cellColor['cel16'] = 'blue'; cellColor['cel8'] = 'blue'; const a = cellColor['cel32'] === cellColor['cel24']; console.log(a); // true const b = cellColor['cel16']; const c = a === b; console.log(c); // true is not equal to 'blue' so return false const d = c === cellColor['cel8']; console.log(d); // false is not equal to 'blue' so return false const e = d === 'blue'; console.log(e);// false is not equal to 'blue' so return false

about 4 years ago · Santiago Gelvez Report
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