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Postgresql - create table with disjoint subclasses

I'm unsure how one can create a table on postgresql with disjoint subclasses. I have represented (a very simplified version of) my problem below in an ER diagram, showing the two subclasses and the attributes of each subclass.

For the columns common to all rows (id, common1, common2), it's clearly very simple (as shown in the code below).

create table Music (
    id          serial,
    common1 int not null, 
    common2 boolean not null, 

--<what to put here???>

);

However I'm not sure of the best way of considering the subclass issue. Does anyone know where to go from here?

9 months ago · Santiago Trujillo

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Accepted Answer · 2022-05-11T21:02:17.679Z

Postgres table inheritance would work like so:

create table music (
    id serial primary key,
    common1 int not null, 
    common2 boolean not null
);

create table symphony (
    layers int not null,
    at1 text not null
) inherits(music);

create table concerto (
    lead text not null,
    strings integer not null
) inherits(music);

Consider if we have a row in each table.

insert into concerto (common1, common2, lead, strings)
  values (1, true, 'a', 5);
insert into symphony (common1, common2, layers, at1)
  values (2, false, 3, 'b');
insert into music (common1, common2)
  values (3, true);

They are all rows of music.

-- Fetches id, common1, and common2 from all rows.
select *
from music

If you only want to query rows in music specify only music.

-- Fetches id, common1, and common2 from only the one row in music.
select *
from only music

If you want to use symphony columns, you have to query symphony.

-- Fetches id, common1, common2, layers, at1 only from symphony
select *
from symphony

Try it

A more traditional structure would use join tables like so:

create table music (
    id serial primary key,
    common1 int not null, 
    common2 boolean not null
);

create table music_symphony (
    music_id integer references music(id),
    layers int not null,
    at1 text not null
);

create table music_concerto (
    music_id integer references music(id),
    lead text not null,
    strings integer not null
);

insert into music (id, common1, common2)
  values (1, 1, true);
insert into music_concerto(lead, strings)
  values ('a', 5);

insert into music (id, common1, common2)
  values (2, 2, false);
insert into music_symphony (music_id, layers, at1)
  values (2, 3, 'b');
  
insert into music (id, common1, common2)
  values (3, 3, true);

-- Fetch all symphonies
select *
from music m
join music_symphony ms on ms.music_id = m.id

Try it