I got a date with format 'Y-m-d', and want to get the day from it. Like if I have 2021.01.01, I want for example Friday, or Thursday depending on what day it actually is. I already got the date stored as $date and I want the day stored as $day
.
I've already tried this, without any error, and without anything happening:
$day = Carbon::createFromFormat('Y-m-d', $date)->format('1');
var_dump($day);
You can try this ,
$d=unixtojd(mktime(0,0,0,6,20,2007));
var_dump(cal_from_jd($d,CAL_GREGORIAN));
output :
array (size=9)
'date' => string '6/20/2007' (length=9)
'month' => int 6
'day' => int 20
'year' => int 2007
'dow' => int 3
'abbrevdayname' => string 'Wed' (length=3)
'dayname' => string 'Wednesday' (length=9)
'abbrevmonth' => string 'Jun' (length=3)
'monthname' => string 'June' (length=4)
And for your code , you just need to add your date like this
$d=unixtojd(mktime(0,0,0,month,days,year));
$calendar = cal_from_jd($d,CAL_GREGORIAN);
var_dump($calendar['dayname']);
I've found another solution for you :
$timestamp = strtotime('2009-10-22');
$day = date('l', $timestamp);
echo $days;
output:
Thursday
It seems like you used a 1 (one) instead of an l (lowercase L). If you change that, it works fine.
$day = Carbon::createFromFormat('Y-m-d', $date)->format('l');
var_dump($day);